Solve the following equation for x:
log23\text{log}_{\sqrt[3]{2}}log32x = 3
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Given,
⇒log23x=3⇒x=(23)3⇒x=(213)3⇒x=2.\Rightarrow \text{log}_{\sqrt[3]{2}}x = 3 \\[1em] \Rightarrow x = (\sqrt[3]{2})^3 \\[1em] \Rightarrow x = (2^{\dfrac{1}{3}})^3 \\[1em] \Rightarrow x = 2.⇒log32x=3⇒x=(32)3⇒x=(231)3⇒x=2.
Hence, x = 2.
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log√3(x + 1) = 2
log4(2x + 3) = 32\dfrac{3}{2}23
log2(x2 - 1) = 3
log x = -1
