Solve the following equation:
log(2x + 3) = log 7
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Given,
⇒ log(2x + 3) = log 7
⇒ 2x + 3 = 7
⇒ 2x = 4
⇒ x = 2.
Hence, x = 2.
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Prove the following:
3log 4 = 4log 3
27log 2 = 8log 3
log(x + 1) + log(x - 1) = log 24
log(10x + 5) - log(x - 4) = 2