Solve the following systems of simultaneous linear equations by cross-multiplication method :

3x - 7y + 10 = 0

y - 2x = 3

Given equations can be written as,

3x - 7y + 10 = 0

-2x + y - 3 = 0

By cross multiplication method,

$\therefore \dfrac{x}{(-7) \times (-3) - 1 \times 10} = \dfrac{y}{10 \times (-2) - (-3) \times 3} = \dfrac{1}{3 \times 1 - (-2) \times (-7)} \\[1em] \Rightarrow \dfrac{x}{21 - 10} = \dfrac{y}{-20 + 9} = \dfrac{1}{3 - 14} \\[1em] \Rightarrow \dfrac{x}{11} = \dfrac{y}{-11} = \dfrac{1}{-11} \\[1em] \therefore \dfrac{x}{11} = \dfrac{1}{-11} \text{ and } \dfrac{y}{-11} = \dfrac{1}{-11} \\[1em] \Rightarrow x = -1 \text{ and } y = 1.$

Hence, x = -1 and y = 1.