Solve for x:
3x=133^x = \dfrac{1}{3}3x=31
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Given,
⇒3x=13⇒3x=13⇒3x=3−1\Rightarrow 3^x = \dfrac{1}{3} \\[1em] \Rightarrow 3^x = \dfrac{1}{3} \\[1em] \Rightarrow 3^x = 3^{-1}⇒3x=31⇒3x=31⇒3x=3−1
Equating the exponents,
⇒ x = -1.
Hence, x = -1.
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If 21168 = x4 × y3 × z2, find the values of x, y, z.
If 1960 = 2a × 5b × 7c, find the values of a, b, c. Hence, calculate the value of 2-a × 5-c × 7b
32x + 1 = 1
ab=(ba)1−3x\sqrt{\dfrac{a}{b}} = \Big(\dfrac{b}{a}\Big)^{1-3x}ba=(ab)1−3x
