Solve for x:

2^{(5x - 1)} = 4 × 2^{(3x + 1)}

Given,

⇒ 2^{(5x - 1)} = 4 × 2^{(3x + 1)}

⇒ 2^{(5x - 1)} = 4 × 2^{(3x + 1)}

⇒ 2^{(5x - 1)} = 2² × 2^{(3x + 1)}

⇒ 2^{(5x - 1)} = 2^{(3x + 1 + 2)}

⇒ 2^{(5x - 1)} = 2^{(3x + 3)}

Equating the exponents,

⇒ 5x - 1 = 3x + 3

⇒ 5x - 3x = 3 + 1

⇒ 2x = 4

⇒ x = $\dfrac{4}{2} = 2$

Hence, x = 2.