Chemistry
State how you would convert (i) sulphur (ii) chlorine (iii) sulphur dioxide — to sulphuric acid.
Sulphuric Acid
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Answer
(i) By action of heat on sulphur and nitric acid:
S + 6HNO3 [conc.] ⟶ 6NO2 + 2H2O + H2SO4
(ii) By passage of chlorine through an aqueous solution of sulphur dioxide:
Cl2 + SO2 + 2H2O ⟶ 2HCl + H2SO4
(iii) By oxidation of an aq. soln. of sulphur dioxide:
2SO2 + 2H2O + O2 ⟶ 2H2SO4
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The acid that is a dehydrating as well as a drying agent.
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(i) State how you would convert (a) sulphur (b) iron pyrites to sulphur dioxide in the first step of the Contact process.
(ii) State the conditions i.e. catalyst, promoter, temperature and pressure in the catalytic oxidation of sulphur dioxide to sulphur trioxide in the Contact tower. Give a balanced equation for the same.
(iii) State why the above catalytic oxidation reaction supplies energy.
(iv) Give a reason why – vanadium pentoxide is preferred to platinum during the catalytic oxidation of sulphur dioxide.
(v) Give a reason why the catalyst mass is heated electrically – only initially.
(vi) State why sulphur trioxide vapours are absorbed in concentrated sulphuric acid and not in water to obtain sulphuric acid.