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Chemistry

State your observations when:

(a) Ethylene gas is passed through bromine water

(b) Silver nitrate solution is added to hydrochloric acid.

(c) Barium chloride is added to potassium sulphate solution.

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Answer

(a) When ethylene gas is passed through bromine water, the reddish brown colour of bromine water disappears due to the formation of the colourless dibromoethane.

C2H4 ethene+Br2[inert solvent]CCl4C2H4Br21,2, dibromooethane [ethylene bromide]\underset{\text{ ethene}}{\text{C}2\text{H}4} + \text{Br}2 \xrightarrow[\text{[inert solvent]}]{\text{CCl}4} \underset{\text{1,2, dibromooethane [ethylene bromide]}}{\text{C}2\text{H}4\text{Br}_2}

(b) When silver nitrate reacts with Hydrochloric acid it gives a white precipitate of AgCl which is insoluble in nitric acid but soluble in ammonium hydroxide.

AgNO3 + HCl ⟶ AgCl ↓ + HNO3

(c) Barium chloride reacts with potassium sulphate to form barium sulphate (a white insoluble solid) and potassium chloride.

BaCl2 + K2SO4 ⟶ BaSO4 + 2KCl

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