$\dfrac{2 + \sqrt{3}}{2 - \sqrt{3}} - \dfrac{2 - \sqrt{3}}{2 + \sqrt{3}}$ is equal to:

1. 4

2. $2\sqrt{3}$

3. 1

4. $8\sqrt{3}$

Statement 1: If a = $3\sqrt{3}$ and b = $\dfrac{5}{\sqrt{12}}$, then a x b is irrational.

Statement 2: a x b = $3 \sqrt{3} \times \dfrac{5}{\sqrt{12}} = \dfrac{15 \times \sqrt{3}}{2\sqrt{3}} = \dfrac{15}{2}$

1. Both the statements are true.

2. Both the statements are false.

3. Statement 1 is true, and statement 2 is false.

4. Statement 1 is false, and statement 2 is true.

Assertion (A): $x + \dfrac{1}{x} = 4 \text{ and } \dfrac{1}{x} = 2 + \sqrt{3}, \text{ then x } = 2 - \sqrt{3}$

Reason (R):

$\Rightarrow \dfrac{1}{x} = 2 + \sqrt{3}\\[1em] \Rightarrow x = \dfrac{1}{2 + \sqrt{3}} = 2 - \sqrt{3}$

1. A is true, but R is false.

2. A is false, but R is true.

3. Both A and R are true, and R is the correct reason for A.

4. Both A and R are true, and R is the incorrect reason for A.

Assertion (A): a = 7 + $\sqrt{3}$ and b = 7 - $\sqrt{3}$, then a² - b² = 14

Reason (R): a² - b² = (a + b)(a - b) = 14 x 2 $\sqrt{3}$

1. A is true, but R is false.

2. A is false, but R is true.

3. Both A and R are true, and R is the correct reason for A.

4. Both A and R are true, and R is the incorrect reason for A.