Mathematics
Statement I: 5, 7, 11, 13 and 17 are prime numbers.
Statement II: The smallest natural number is 1.
Statement I is true but statement II is false.
Statement I is false but statement II is true.
Both Statement I and statement II are true.
Both Statement I and statement II are false.
Answer
Statement I: Each of 5, 7, 11, 13 and 17 has exactly two factors (1 and itself). So they are all prime numbers.
∴ Statement I is true.
Statement II: The set of natural numbers is {1, 2, 3, …}, so the smallest natural number is 1.
∴ Statement II is true.
Both statements are true.
Hence, option 3 is the correct option.
Related Questions
If the LCM of two natural numbers is 180, then which of the following is not the HCF of the numbers?
45
60
75
90
Statement I: 4 × 5 = 20. So 20 is a multiple of 4 and 5.
Statement II: If a is a factor of c, then c is called a multiple of a.
Statement I is true but statement II is false.
Statement I is false but statement II is true.
Both Statement I and statement II are true.
Both Statement I and statement II are false.
Statement I: 2, 4, 6 and 9 are composite numbers.
Statement II: A number is said to be a composite number if it has prime factors.
Statement I is true but statement II is false.
Statement I is false but statement II is true.
Both Statement I and statement II are true.
Both Statement I and statement II are false.
Statement I: 41 and 43 is a pair of twin prime numbers.
Statement II: A pair of prime numbers with a difference of 2 are called twin prime numbers.
Statement I is true but statement II is false.
Statement I is false but statement II is true.
Both Statement I and statement II are true.
Both Statement I and statement II are false.