Chemistry
A student prepared a Potassium sulphite solution in the lab and added few drops of barium nitrate solution to it. He observed a white precipitate being formed in the test tube. On addition of dilute hydrochloric acid to the white precipitate and mixing it, he observed that the precipitate disappeared.
(a) Name the white precipitate.
(b) Write a balanced chemical equation for the reaction between dilute hydrochloric acid and the white precipitate.
(c) Name the gas evolved in the above reaction.
Acids Bases Salts
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Answer
(a) When the student mixed potassium sulphite solution (K2SO3) with barium nitrate (Ba(NO3)2), the white precipitate of Barium sulphite (BaSO3) is formed.
K2SO3 + Ba(NO3)2 ⟶ BaSO3 + 2KNO3
(b) When white precipitate of BaSO3 reacts with dilute HCl, it dissolves, forming barium chloride (BaCl2), water, and sulphur dioxide (SO2) gas.
BaSO3 + 2HCl ⟶ BaCl2 + H2O + SO2 ↑
(c) From the above reaction, the gas produced is sulphur dioxide (SO2).
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