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Mathematics

Some students planned a picnic. The budget for the food was ₹ 2,400. As 8 of them failed to join the party, the cost of the food for each member increased by ₹ 50. Find how many students went to the picnic.

Quadratic Equations

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Answer

Let the original number of students be x.

In first case:

Given,

Budget of food = ₹ 2,400

Cost per person = ₹ 2400x\dfrac{2400}{x}

In second case :

Given,

8 students failed to join, number of students who went = x - 8

Cost per person = ₹ 2400x8\dfrac{2400}{x - 8}

When 8 students failed to join the party, the cost of the food for each member increased by ₹ 50.

2400x82400x=502400x2400(x8)x(x8)=502400x2400x+19200x28x=5019200=50(x28x)1920050=(x28x)384=x28xx28x384=0x224x+16x384=0x(x24)+16(x24)=0(x+16)(x24)=0(x+16)=0 or (x24)=0….[Using zero-product rule]x=16 or x=24\therefore \dfrac{2400}{x - 8} - \dfrac{2400}{x} = 50 \\[1em] \Rightarrow \dfrac{2400x - 2400(x - 8)}{x(x - 8)} = 50 \\[1em] \Rightarrow \dfrac{2400x - 2400x + 19200}{x^2 - 8x} = 50 \\[1em] \Rightarrow 19200 = 50(x^2 - 8x) \\[1em] \Rightarrow \dfrac{19200}{50} = (x^2 - 8x) \\[1em] \Rightarrow 384 = x^2 - 8x \\[1em] \Rightarrow x^2 - 8x - 384 = 0 \\[1em] \Rightarrow x^2 - 24x + 16x - 384 = 0 \\[1em] \Rightarrow x(x - 24) + 16(x - 24) = 0 \\[1em] \Rightarrow (x + 16)(x - 24) = 0 \\[1em] \Rightarrow (x + 16) = 0 \text{ or } (x - 24) = 0 \text{….[Using zero-product rule]} \\[1em] \Rightarrow x = -16 \text{ or } x = 24

Since, number of students cannot be negative.

Thus, x = 24.

Hence, number of students went to picnic = 24.

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