Subtract:

$\dfrac{2}{3}$ from $\dfrac{5}{6}$

To subtract one rational number from another, add the additive inverse of the rational number to be subtracted.

Subtracting $\dfrac{2}{3}$ from $\dfrac{5}{6}$,

LCM of 6 and 3 = 6

$\dfrac{5}{6} - \dfrac{2}{3} = \dfrac{5 - 2 \times 2}{6} \\[1em] = \dfrac{5 - 4}{6} \\[1em] = \dfrac{1}{6}$

Hence, the required difference is $\mathbf{\dfrac{1}{6}}$.