Subtract:

$\dfrac{-11}{6}$ from $\dfrac{8}{3}$

To subtract one rational number from another, add the additive inverse of the rational number to be subtracted.

Subtracting $\dfrac{-11}{6}$ from $\dfrac{8}{3}$,

LCM of 3 and 6 = 6

$\dfrac{8}{3} - \left(\dfrac{-11}{6}\right) = \dfrac{8}{3} + \dfrac{11}{6} \\[1em] = \dfrac{8 \times 2 + 11}{6} \\[1em] = \dfrac{16 + 11}{6} \\[1em] = \dfrac{27}{6} = \dfrac{9}{2} \\[1em] = 4\dfrac{1}{2}$

Hence, the required difference is $\mathbf{4\dfrac{1}{2}}$.