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Mathematics

Sum of n terms of an A.P. whose first term is a and common difference is d, is given by:

  1. Sn = n2[a+(n1)d]\dfrac{n}{2}[a + (n − 1)d]

  2. Sn = n2[2a+(n+1)d]\dfrac{n}{2}[2a + (n + 1)d]

  3. Sn = n2[2a(n1)d]\dfrac{n}{2}[2a − (n − 1)d]

  4. Sn = n2[2a+(n1)d]\dfrac{n}{2}[2a + (n − 1)d]

AP

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Answer

Sum of n terms of an A.P. is given by,

∴ Sn = n2\dfrac{n}{2}[2a + (n - 1)d]

Hence, option 4 is the correct option.

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