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Mathematics

The sum of the successor and the predecessor of a number is 1326. The number is

  1. 663

  2. 662

  3. 664

  4. 661

Number System

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Answer

Let the number be N.

The successor of the number is N + 1.

The predecessor of the number is N − 1.

According to the problem, the sum of the successor and the predecessor is 1326:

⇒ (N + 1) + (N − 1) = 1326

⇒ N + 1 + N − 1 = 1326

⇒ 2N = 1326

⇒ N = 13262\dfrac{1326}{2}

⇒ N = 663

Hence, option 1 is the correct option.

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