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Mathematics

The sum of two numbers exceeds thrice the smaller by 2. If the difference between them is 19, find the numbers.

Linear Equations

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Answer

Let the numbers be x and y, such that x < y.

Given,

The sum of two numbers exceeds thrice the smaller by 2.

∴ (x + y) - 3x = 2

⇒ x - 3x + y = 2

⇒ y - 2x = 2     ……(1)

Given,

Difference between the numbers = 19

⇒ y - x = 19     ……(2)

Subtracting equation (1) from (2), we get:

⇒ y - x - (y - 2x) = 19 - 2

⇒ y - x - y + 2x = 19 - 2

⇒ x = 17.

Substituting value of x in equation (1), we get :

⇒ y - 2x = 2

⇒ y - 2 × 17 = 2

⇒ y - 34 = 2

⇒ y = 36.

Hence, the numbers are 17 and 36.

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