Sunita is 24 years older than her daughter Kavita. 6 years ago, Sunita was thrice as old as Kavita. Find their present ages.

Let Kavita's present age be x years.

Then, Sunita's present age = (x + 24) years.

6 years ago:

Kavita's age = (x - 6) years.

Sunita's age = (x + 24 - 6) years = (x + 18) years.

According to the question, 6 years ago, Sunita was thrice as old as Kavita:

∴ x + 18 = 3(x - 6)

⇒ x + 18 = 3x - 18

⇒ 18 + 18 = 3x - x $\quad$ [Transposing +x to RHS and -18 to LHS]

⇒ 36 = 2x

⇒ x = $\dfrac{36}{2}$

⇒ x = 18

Kavita's present age = x years = 18 years.

Sunita's present age = (x + 24) years = (18 + 24) years = 42 years.

Hence, Sunita's present age is 42 years and Kavita's present age is 18 years.