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A swimming pool is 30 m long and 12 m broad. Its shallow and deep ends are 1.5 m and 3.5 m deep respectively. If the bottom of the pool slopes uniformly, how many litres of water will fill the pool?

A swimming pool is 30 m long and 12 m broad. Its shallow and deep ends are 1.5 m and 3.5 m deep respectively. If the bottom of the pool slopes uniformly, how many litres of water will fill the pool. Volume and Surface Area of Solids, R.S. Aggarwal Mathematics Solutions ICSE Class 9.

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Answer

From figure,

The swimming pool cross-section is in the shape of trapezium.

Area of cross-section = 12× (Sum of // sides)× (Distance between them)\dfrac{1}{2} \times \text{ (Sum of // sides)} \times \text{ (Distance between them)}

= 12×(1.5+3.5)×30\dfrac{1}{2} \times (1.5 + 3.5) \times 30

= 75 m2.

Volume of pool = Area of cross-section × length

= 75 × 12

= 900 m3

= 900 × 1000 liters

= 900000 litres.

Hence, 900000 litres of water will fill the pool.

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