Taking A = 60° and B = 30°, verify that (i) sin(A + B)/cosA cosB = tanA + tanB (ii) sin(A - B)/sinA sinB = cotB - cotA

Question

KnowledgeBoat · Accepted Answer

(i) To verify, . Substituting value of A and B in L.H.S. of the equation, we get : Substituting value of A and B in R.H.S. of the equation, we get : Since, L.H.S. = R.H.S. Hence, proved that . (ii) To verify, Substituting value of A and B in L.H.S. of the equation, we get : Substituting value of A and B in R.H.S. of the equation, we get : ⇒ cot B - cot A ⇒ cot 30° - cot 60° ⇒ ⇒ . Since, L.H.S. = R.H.S. Hence, proved that .

Mathematics

Taking A = 60° and B = 30°, verify that (i) sin(A + B)/cosA cosB = tanA + tanB (ii) sin(A - B)/sinA sinB = cotB - cotA

Trigonometrical Ratios

Related Questions

Taking A = 30°, verify that
(i) cos⁴ A - sin⁴ A = cos 2A
(ii) 4 cos A cos (60° - A) cos (60° + A) = cos 3A.

If 3θ is an acute angle, solve the following equation for θ :
(cosec 3θ - 2)(cot 2θ - 1) = 0.

Mathematics

Taking A = 60° and B = 30°, verify that (i) sin(A + B)/cosA cosB = tanA + tanB (ii) sin(A - B)/sinA sinB = cotB - cotA

Trigonometrical Ratios

Related Questions

Taking A = 30°, verify that(i) cos4 A - sin4 A = cos 2A(ii) 4 cos A cos (60° - A) cos (60° + A) = cos 3A.

If 3θ is an acute angle, solve the following equation for θ :(cosec 3θ - 2)(cot 2θ - 1) = 0.

Taking A = 30°, verify that
(i) cos⁴ A - sin⁴ A = cos 2A
(ii) 4 cos A cos (60° - A) cos (60° + A) = cos 3A.

If 3θ is an acute angle, solve the following equation for θ :
(cosec 3θ - 2)(cot 2θ - 1) = 0.