Mathematics
Which term of the G.P. 2, 8, 32, 128, …….. is 131072?
9th
10th
8th
12th
G.P.
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Answer
In the given G.P.,
a = 2
r = = 4
We know that,
Tn = arn - 1
Let nth term be 131072.
⇒ Tn = 131072
⇒ 2.(4)n - 1 = 131072
⇒ (22)n - 1 =
⇒ 22n - 2 = 65536
⇒ 22n - 2 = 216
Equate exponents:
⇒ 2n - 2 = 16
⇒ 2n = 16 + 2
⇒ 2n = 18
⇒ n = = 9.
Hence, option 1 is the correct option.
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