The 15th term from the last of the A.P. 7, 10, 13, … , 130 is

1. 49

2. 85

3. 88

4. 110

Here, common difference = d = 10 - 7 = 3 and last term = l = 130.

We know that the nth term from the end is given by the formula:

    nth term from end = l - (n - 1)d
∴ 11th term from the end = 130 - (15 - 1) × 3 = 130 - 14 × 3 = 130 - 42 = 88.

Hence, Option 3 is the correct option.