The 24th term of an A.P. exceeds its 19 th term by 10, its common difference is : 1. 5 2. 2 3. 10 4. 1

Let first term of A.P. be a and common difference be d. By formula, ⇒ a n = a + (n - 1)d ⇒ a 24 = a + (24 - 1)d = a + 23d. ⇒ a 19 = a + (19 - 1)d = a + 18d. Given, 24th term exceeds 19 th term by 10. ⇒ a 24 - a 19 = 10 ⇒ a + 23d - (a + 18d) = 10 ⇒ a - a + 23d - 18d = 10 ⇒ 5d = 10 ⇒ d = = 2. Hence, Option 2 is the correct option.

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no
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14
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Mathematics

The 24th term of an A.P. exceeds its 19^th term by 10, its common difference is :
5
2
10
1

AP GP

Related Questions

Is -8, -8, -8, -8, ….. an A.P.?
no
yes
may be
none of the above

The 15^th term of the A.P. 3, 0, -3, -6, …… is :
-42
39
42
-39

In the A.P. 8, 13, 18, ……., the n^th term is 83, then n is equal to :
14
16
13
15

The n^th term of a sequence is (2n - 3), find the fifteenth term.

Mathematics

The 24th term of an A.P. exceeds its 19th term by 10, its common difference is :52101

AP GP

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Is -8, -8, -8, -8, ….. an A.P.?noyesmay benone of the above

The 15th term of the A.P. 3, 0, -3, -6, …… is :-423942-39

In the A.P. 8, 13, 18, ……., the nth term is 83, then n is equal to :14161315

The nth term of a sequence is (2n - 3), find the fifteenth term.

The 24th term of an A.P. exceeds its 19^th term by 10, its common difference is :
5
2
10
1

Is -8, -8, -8, -8, ….. an A.P.?
no
yes
may be
none of the above

The 15^th term of the A.P. 3, 0, -3, -6, …… is :
-42
39
42
-39

In the A.P. 8, 13, 18, ……., the n^th term is 83, then n is equal to :
14
16
13
15

The n^th term of a sequence is (2n - 3), find the fifteenth term.