The age of a father is twice the square of the age of his son. Eight years hence, the age of the man will be 4 years more than 3 times the age of his son. Find their present ages.
Quadratic Equations
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Question

The age of a father is twice the square of the age of his son. Eight years hence, the age of the man will be 4 years more than 3 times the age of his son. Find their present ages.

KnowledgeBoat · Accepted Answer

Let son's present age be x years Man's age = 2x² After 8 years, Son's age = (x + 8) years Man's age = (2x² + 8) According to question, Since, age cannot be negative hence x ≠ ∴ x = 4 , 2x² = 32 The present age of son is 4 years while the age of man is 32 years.

Mathematics

The age of a father is twice the square of the age of his son. Eight years hence, the age of the man will be 4 years more than 3 times the age of his son. Find their present ages.

Quadratic Equations

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