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Mathematics

The amount, of ₹ 1,000 invested for 2 years at 5% per annum compounded annually is:

  1. ₹ 1,100

  2. ₹ 1,102.50

  3. ₹ 1,200

  4. ₹ 8,000

Simple Interest

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Answer

Given:

P = ₹ 1,000

R = 5%

n = 2 years

A=P[1+R100]n=1,000[1+5100]2=1,000[1+120]2=1,000[2020+120]2=1,000[(20+1)20]2=1,000[2120]3=1,000[441400]=[4,41,000400]=1,102.50\text{A} = P\Big[1 + \dfrac{R}{100}\Big]^n\\[1em] = 1,000\Big[1 + \dfrac{5}{100}\Big]^2\\[1em] = 1,000\Big[1 + \dfrac{1}{20}\Big]^2\\[1em] = 1,000\Big[\dfrac{20}{20} + \dfrac{1}{20}\Big]^2\\[1em] = 1,000\Big[\dfrac{(20 + 1)}{20}\Big]^2\\[1em] = 1,000\Big[\dfrac{21}{20}\Big]^3\\[1em] = 1,000\Big[\dfrac{441}{400}\Big]\\[1em] = \Big[\dfrac{4,41,000}{400}\Big]\\[1em] = 1,102.50

Hence, option 2 is the correct option.

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