The area of a rectangular paper is $7\dfrac{1}{3}$ cm². If its length $4\dfrac{2}{5}$cm, its breadth is:

1. $1\dfrac{3}{5}$cm

2. $1\dfrac{2}{3}$cm

3. $\dfrac{3}{5}$cm

4. $\dfrac{25}{60}$cm

Let breadth be b

Length = $4\dfrac{2}{5}$cm = $\dfrac{22}{5}$cm.

Area = $7\dfrac{1}{3}$ cm² =$\dfrac{22}{3}$ cm².

Area of rectangle = length x breadth $\dfrac{22}{3} = \dfrac{22}{5} \times b\\[1em] ⇒ b = \dfrac{22}{3} ÷ \dfrac{22}{5}\\[1em] ⇒ b = \dfrac{22}{3} \times \dfrac{5}{22}\\[1em] ⇒ b = \dfrac{22 \times 5}{3 \times 22} \\[1em] ⇒ b = \dfrac{110}{66}\\[1em] ⇒ b = \dfrac{5}{3}\\[1em] ⇒ b = 1\dfrac{2}{3}$

Hence, option 2 is the correct option.