The area of base of a cylindrical vessel is 300 cm 2 . Water (density = 1000 kg m -3 ) is poured into it up to a depth of 6 cm. Calculate (a) the pressure and (b) the thrust of water on the base. (g = 10 m s -2 ).

(a) As we know, Pressure due to water column of height h = hρg Given, ρ = 1000 kg m -3 g = 10 m s -2 h = 6 cm Converting cm to m 100 cm = 1 m So, 6 cm = x 6 = 0.06 m Hence, h = 0.06 m Substituting the values in the formula above we get, Hence, Pressure = 600 Pa (b) As we know, Pressure (P) = A = 300 cm 2 Converting cm 2 into m 2 100 cm = 1 m So, 100 cm x 100 cm = 1 m 2 Hence, 300 cm 2 = Therefore, A = 3 x 10 -2 m 2 Substituting the values in the formula we get, Hence, thrust = 18 N

A block of iron of mass 7.5 kg and of dimensions 12 cm x 8 cm x 10 cm is kept on a table top on it's base of side 12 cm x 8 cm. Calculate (a) thrust and (b) pressure exerted on the table top. Take 1 kgf = 10 N.

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A vessel contains water up to a height of 1.5 m. Taking the density of water 10 ³ kg m ^-3, acceleration due to gravity 9.8 m s ^-2 and area of base vessel 100 cm ², calculate (a) the pressure and (b) the thrust, at the base of vessel.

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(a) Calculate the height of a water column which will exert on it's base the same pressure as the 70 cm column of mercury. Density of mercury is 13.6 g cm^-3.
(b) Will the height of the water column in part (a) change if the cross section of the water column is made wider ?

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The pressure of water on the ground floor is 40,000 Pa and on the first floor is 10,000 Pa. Find the height of the first floor.
(Take : density of water = 1000 kg m^-3, g = 10 m s^-2)

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Physics

The area of base of a cylindrical vessel is 300 cm ². Water (density = 1000 kg m ^-3) is poured into it up to a depth of 6 cm. Calculate (a) the pressure and (b) the thrust of water on the base. (g = 10 m s^-2).

Fluids Pressure

Related Questions

A block of iron of mass 7.5 kg and of dimensions 12 cm x 8 cm x 10 cm is kept on a table top on it's base of side 12 cm x 8 cm. Calculate (a) thrust and (b) pressure exerted on the table top. Take 1 kgf = 10 N.

A vessel contains water up to a height of 1.5 m. Taking the density of water 10 ³ kg m ^-3, acceleration due to gravity 9.8 m s ^-2 and area of base vessel 100 cm ², calculate (a) the pressure and (b) the thrust, at the base of vessel.

(a) Calculate the height of a water column which will exert on it's base the same pressure as the 70 cm column of mercury. Density of mercury is 13.6 g cm^-3.
(b) Will the height of the water column in part (a) change if the cross section of the water column is made wider ?

The pressure of water on the ground floor is 40,000 Pa and on the first floor is 10,000 Pa. Find the height of the first floor.
(Take : density of water = 1000 kg m^-3, g = 10 m s^-2)

Physics

The area of base of a cylindrical vessel is 300 cm 2. Water (density = 1000 kg m -3) is poured into it up to a depth of 6 cm. Calculate (a) the pressure and (b) the thrust of water on the base. (g = 10 m s-2).

Fluids Pressure

Related Questions

A block of iron of mass 7.5 kg and of dimensions 12 cm x 8 cm x 10 cm is kept on a table top on it's base of side 12 cm x 8 cm. Calculate (a) thrust and (b) pressure exerted on the table top. Take 1 kgf = 10 N.

A vessel contains water up to a height of 1.5 m. Taking the density of water 10 3 kg m -3, acceleration due to gravity 9.8 m s -2 and area of base vessel 100 cm 2, calculate (a) the pressure and (b) the thrust, at the base of vessel.

(a) Calculate the height of a water column which will exert on it's base the same pressure as the 70 cm column of mercury. Density of mercury is 13.6 g cm-3.(b) Will the height of the water column in part (a) change if the cross section of the water column is made wider ?

The pressure of water on the ground floor is 40,000 Pa and on the first floor is 10,000 Pa. Find the height of the first floor.(Take : density of water = 1000 kg m-3, g = 10 m s-2)

The area of base of a cylindrical vessel is 300 cm ². Water (density = 1000 kg m ^-3) is poured into it up to a depth of 6 cm. Calculate (a) the pressure and (b) the thrust of water on the base. (g = 10 m s^-2).

A vessel contains water up to a height of 1.5 m. Taking the density of water 10 ³ kg m ^-3, acceleration due to gravity 9.8 m s ^-2 and area of base vessel 100 cm ², calculate (a) the pressure and (b) the thrust, at the base of vessel.

(a) Calculate the height of a water column which will exert on it's base the same pressure as the 70 cm column of mercury. Density of mercury is 13.6 g cm^-3.
(b) Will the height of the water column in part (a) change if the cross section of the water column is made wider ?

The pressure of water on the ground floor is 40,000 Pa and on the first floor is 10,000 Pa. Find the height of the first floor.
(Take : density of water = 1000 kg m^-3, g = 10 m s^-2)