Chemistry
Answer
FeSO4
Reason — In the brown ring test the conc. sulphuric acid being heavier settles down and the iron [II] sulphate layer remains above it resulting in formation of the brown ring at the junction.
6FeSO4 + 3H2SO4 + 2HNO3 (dil. ) ⟶ 3Fe2(SO4)3 + 4H2O +2NO
FeSO4 + NO ⟶ FeSO4.NO
[Nitroso Ferrous sulphate, a brown compound]
Related Questions
Correct the following, if required:
(a) HNO3 is a strong reducing agent.
(b) NaNO3 gives NO2 and O2 on heating.
(c) Constant boiling nitric acid contains 80% nitric acid by weight.
(d) Nitric acid remains colourless even when exposed to light.
(e) Magnesium reacts with nitric acid to liberate hydrogen gas.
The nitrate salt which does not give a mixture of NO2 and O2 on heating is:
- AgNO3
- KNO3
- Cu(NO3)2
- Zn(NO3)2
Lead nitrate decomposes on heating to give:
- NO
- N2O
- NO2
- N2O5
In the laboratory preparation of nitric acid, nitre is heated with :
- conc. HCl
- conc. H2SO4
- dil. H2SO4
- conc. H3PO4