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Mathematics

The C.I. on ₹ 16000 in 2 years at the rate of 20% per annum is :

  1. ₹ 19360

  2. ₹ 7040

  3. ₹ 23040

  4. ₹ 22400

Compound Interest

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Answer

Given,

P = ₹ 16000

n = 2 years

r = 20%

By formula,

A = P(1+r100)nP\Big(1 + \dfrac{r}{100}\Big)^n

C.I. = A - P

C.I.=P(1+r100)nP=16000×(1+20100)216000=16000×(120100)216000=16000×(65)216000=16000×362516000=2304016000=7040.C.I. = P\Big(1 + \dfrac{r}{100}\Big)^n - P \\[1em] = 16000 \times \Big(1 + \dfrac{20}{100}\Big)^2 - 16000 \\[1em] = 16000 \times \Big(\dfrac{120}{100}\Big)^2 - 16000 \\[1em] = 16000 \times \Big(\dfrac{6}{5}\Big)^2 - 16000 \\[1em] = 16000 \times \dfrac{36}{25} - 16000 \\[1em] = 23040 - 16000 \\[1em] = ₹ 7040.

Hence, Option 2 is the correct option.

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