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Mathematics

The circumference of a circular field is 308 m. Find its :

(i) radius

(ii) area.

Mensuration

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Answer

(i) Let r be the radius of the circle.

The circumference of a circle = 308 m

As we know, the circumference of a circle = 2πr

2×227×r=308447×r=308r=308×744r=2,15644r=49 m2⇒ 2 \times \dfrac{22}{7} \times r = 308\\[1em] ⇒ \dfrac{44}{7} \times r = 308\\[1em] ⇒ r = \dfrac{308 \times 7}{44}\\[1em] ⇒ r = \dfrac{2,156}{44}\\[1em] ⇒ r = 49 \text{ m}^2

Hence, the radius of a circle is 49 m.

(ii) Area of a circle = πr2

=227×492=227×2,401=52,8227=7,546 m2= \dfrac{22}{7} \times 49^2\\[1em] = \dfrac{22}{7} \times 2,401\\[1em] = \dfrac{52,822}{7}\\[1em] = 7,546 \text{ m}^2

Hence, the area of a circle is 7,546 m2.

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