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Mathematics

The cost price of an article is 25% below the marked price. If the article is available at 15% discount and its cost price is ₹ 2,400, find:

(i) its marked price

(ii) its selling price

(iii) the profit percent.

Profit, Loss & Discount

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Answer

(i) Given:

C.P. = 25% below the M.P.

C.P. = ₹ 2,400

Let the M.P. be ₹ xx.

x25100×x=2,400x14×x=2,4004x4x4=2,400(4xx)4=2,4003x4=2,400x=2,400×43x=9,6003x=3,200x - \dfrac{25}{100} \times x = 2,400\\[1em] \Rightarrow x - \dfrac{1}{4} \times x = 2,400\\[1em] \Rightarrow \dfrac{4x}{4} - \dfrac{x}{4} = 2,400\\[1em] \Rightarrow \dfrac{(4x - x)}{4} = 2,400\\[1em] \Rightarrow \dfrac{3x}{4} = 2,400\\[1em] \Rightarrow x = \dfrac{2,400 \times 4}{3}\\[1em] \Rightarrow x = \dfrac{9,600}{3}\\[1em] \Rightarrow x = ₹ 3,200

Hence, the marked price = ₹ 3,200.

(ii) M.P. of the article = ₹ 3,200

Discount = 15% of M.P.

15100×3,200320×3,2009,60020480\Rightarrow \dfrac{15}{100} \times ₹ 3,200\\[1em] \Rightarrow \dfrac{3}{20} \times ₹ 3,200\\[1em] \Rightarrow₹ \dfrac{9,600}{20}\\[1em] \Rightarrow₹ 480

S.P. of the article = M.P. - Discount

= ₹ 3,200 - ₹480

= ₹ 2,720

Hence, the selling price = ₹ 2,720.

(iii) C.P. = ₹ 2,400

S.P. = ₹ 2,720

Profit = S.P. - C.P.

= 2,7202,400₹ 2,720 - ₹ 2,400

= 320₹ 320

And,

Profit%=ProfitC.P.×100=3202400×100%=320002400%=403%=1313%\text{Profit\%} = \dfrac{\text{Profit}}{\text{C.P.}} \times 100\\[1em] = \dfrac{320}{2400} \times 100\%\\[1em] = \dfrac{32000}{2400}\%\\[1em] = \dfrac{40}{3}\%\\[1em] = 13\dfrac{1}{3}\%

Hence, the profit percent = 1313%13\dfrac{1}{3}\%.

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