Mathematics
The daily wages of workers in a construction unit were recorded as follows :
| Class marks (Wages) | No. of workers |
|---|---|
| 425 | 6 |
| 475 | 12 |
| 525 | 15 |
| 575 | 17 |
| 625 | 7 |
| 675 | 13 |
Form a frequency distribution table with class intervals and find modal wage by plotting a histogram.
Statistics
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Answer
Difference between two consecutive class marks = 475 - 425 = 50.
Adjustment factor = = 25.
Lower class limit = Class mark - Adjustment factor
Upper class limit = Class mark + Adjustment factor
| Class | Frequency |
|---|---|
| 400-450 | 6 |
| 450-500 | 12 |
| 500-550 | 15 |
| 550-600 | 17 |
| 600-650 | 7 |
| 650-700 | 3 |
Steps of construction :
Take 2 cm along x-axis = ₹50 and 2 cm along y-axis = 5 workers.
Construct rectangles corresponding to the given data.
In highest rectangle, draw two st. lines AD and BC from corners of the rectangles on either side of the highest rectangle to the opposite corners of the highest rectangle.
Let K be the point of intersection of AD and BC. Through K, draw a vertical line to meet the x-axis at L. The abscissa of the point L represents 557.50.

Hence, mode = ₹ 557.50
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