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The diagram below shows a light source P embedded in a rectangular glass block ABCD of critical angle 42°. The ray PQ would:

The diagram below shows a light source P embedded in a rectangular glass block ABCD of critical angle 42°. Complete the path of the ray PQ till it emerges out of the block. [Write necessary angles.] ICSE 2019 Physics Solved Question Paper.
  1. pass undeviated
  2. suffer refraction
  3. suffer reflection
  4. suffer total internal reflection

Refraction Plane Surfaces

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Answer

suffer total internal reflection

Reason — We can see from the below diagram that the ray is travelling from a denser to a rarer medium and the angle of incidence is greater than the critical angle. In such a case no refracted ray is obtained and the incident ray is reflected back into the same medium. This phenomenon is known as total internal reflection.

The diagram below shows a light source P embedded in a rectangular glass block ABCD of critical angle 42°. Complete the path of the ray PQ till it emerges out of the block. [Write necessary angles]. ICSE 2019 Physics Solved Question Paper.

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