Physics
The diagram shows two forces F1 = 5N and F2 = 3N acting at points A and B of a rod pivoted at a point O, such that OA = 2m and OB = 4m
Calculate:
(i) the moment of force F1 about O.
(ii) the moment of force F2 about O.
(iii) total moment of the two forces about O.
Force
228 Likes
Answer
Given,
OA = 2m
OB = 4m
F1 = 5N
F2 = 3N
As we know,
Moment of force = F x r
Substituting the values of F and r
(i) Moment of force F1 about O
Therefore, moment of force F1 about O is 10Nm (anticlockwise)
(ii) Moment of force F2 about O
Therefore, moment of force F2 about O is 12Nm (clockwise)
(iii) Total moment of two forces about midpoint is
Therefore, total moment of two forces about O is 2Nm (clockwise)
Answered By
162 Likes
Related Questions
A mechanic applies a force of 100 N at the end of a spanner to tighten a bolt. The length of the spanner is 0.5 metres. How much torque is exerted on the bolt? If the mechanic increases the force applied by 20% but holds the spanner closer at 0.4 metres, would it result in an increase or decrease of torque?
A wheel of diameter 2m is shown in figure with axle at O. A force F = 2N is applied at B in the direction shown in figure.
Calculate the moment of force about
(i) the centre O, and
(ii) the point A.
Two forces each of magnitude 10N act vertically upwards and downwards respectively at the two ends A and B of a uniform rod of length 4m which is pivoted at its mid-point O as shown. Determine the magnitude of resultant moment of forces about the pivot O.
Figure shows two forces each of magnitude 10N acting at the points A and B at a separation of 50 cm, in opposite directions. Calculate the resultant moment of the two forces about the point (i) A, (ii) B and (iii) O, situated exactly at the middle of the two forces.
