Chemistry
The empirical formula of an organic compound is C3H4N. Its molecular weight is 108. Find the amount of carbon in one mole of the compound. Show all the steps involved.
(Atomic weights: C- 12; H- 1; N- 14)
Stoichiometry
ICSE Sp 2024
93 Likes
Answer
Empirical formula is C3H4N
Empirical formula weight = (3 x 12) + (4 x 1) + (1 x 14)
= 36 + 4 + 14
= 54
Molecular weight = 108
∴ Molecular formula = (C3H4N) x 2 = C6H8N2
No. of carbon atoms in 1 mole of C6H8N2 = 6
∴ Mass of carbon in one mole of the compound (C6H8N2) = 6 x 12 = 72 g
Hence, in 1 mole of the compound (C6H8N2), there is 72 grams of carbon.
Answered By
42 Likes
Related Questions
Copper sulphate solution is electrolysed using copper electrodes.
(a) Which electrode [cathode or anode] is the oxidizing electrode? Why?
(b) Write the equation for the reaction occurring at the above electrode.
X [2, 8, 7] and Y [2, 8, 2] are two elements. Using this information complete the following:
(a) …………… is the metallic element.
(b) Metal atoms tend to have a maximum of …………… electrons in the outermost shell.
(c) …………… is the reducing agent.
(a) Mahesh prepared a basic solution X that has a pH 7. How will the pH of the solution X change on addition of the following:
Hydrochloric acid
a solution of a base
(b) The atomic number of an element is 15. To which group will this element belong to?
8.2 grams of calcium nitrate is decomposed by heating according to the equation
2Ca(NO3)2 ⟶ 2CaO + 4NO2 + O2
Calculate the following:
(a) Volume of nitrogen dioxide obtained at STP
(b) Mass of CaO formed
[Atomic weights: Ca –40 , N—14, O—16]