The equation 2x2 - 3x + k = 0 is satisfied by x = 2; the value of k is :
-2
2
4
3
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Given,
x = 2 satisfies the equation 2x2 - 3x + k = 0.
∴ 2(2)2 - 3(2) + k = 0
⇒ 2(4) - 6 + k = 0
⇒ 8 - 6 + k = 0
⇒ k + 2 = 0
⇒ k = -2.
Hence, Option 1 is the correct option.
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(x - 3)(x + 5) = 0 gives x equal to :
3 or 5
3 or -5
3 and -5
If 4 is a root of the equation x2 + kx - 4 = 0; the value of k is :
-3
If x2 - 7x = 0; the value of x is :
0 and 7
7
0
0 or 7
Find which of the following equations are quadratic :
5x2 - 8x = -3(7 - 2x)