Chemistry
The equation for the burning of octane is :
2C8H18 + 25O2 ⟶ 16CO2 + 18H2O
(i) How many moles of carbon dioxide are produced when one mole of octane burns ?
(ii) What volume, at s.t.p., is occupied by the number of moles determined in (i) ?
(iii) If the relative molecular mass of carbon dioxide is 44, what is the mass of carbon dioxide produced by burning two moles of octane ?
Stoichiometry
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Answer
(i) 2 moles of octane produce 16 moles of carbon dioxide
∴ 1 mole of octane will produce = 8 moles of carbon dioxide.
(ii) 1 moles occupies 22.4 lit. of vol.
∴ 8 mole will occupy x 8 = 179.2 lit. of vol.
(iii) To calculate the mass of CO2 produced :
Mass of 1 mole of CO2 = 44 g
∴ Mass of 16 moles of CO2 = 44 x 16 = 704 g
Hence, 8 moles of carbon dioxide are produced, vol occupied is 179.2 lit. and mass of carbon dioxide produced is 704 g
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