The figure (ii) given below shows a field with the measurements given in metres. Find the area of the field.
Mensuration
54 Likes

Question

The figure (ii) given below shows a field with the measurements given in metres. Find the area of the field.

KnowledgeBoat · Accepted Answer

From figure, Area of right angled △AXB = × base × height = × BX × AX = × 30 × 12 = 180 m². Area of trapezium XZCB = (sum of parallel sides) × distance between them = × (BX + CZ) × 15 = × (30 + 25) × 15 = × 55 × 15 = 412.5 cm². Area of right angled △CZD = × base × height = × CZ × ZD = × 25 × 10 = 125 m². Area of △AED = × base × height = × AD × EY = × 37 × 20 = 370 m². Area of field = Area of right angled △AXB + Area of trapezium XZCB + Area of right angled △CZD + Area of △AED = 180 + 412.5 + 125 + 370 = 1087.5 m². Hence, area of field = 1087.5 m².

Mathematics

The figure (ii) given below shows a field with the measurements given in metres. Find the area of the field.

Mensuration

Related Questions

In the figure (iii) given below, from a 24 cm × 24 cm piece of cardboard, a block in the shape of letter M is cut off. Find the area of the cardboard left over, all measurements are in centimetres.

The figure (i) given below shows the cross-section of the concrete structure with the measurements as given. Calculate the area of cross-section.

Calculate the area of the pentagon ABCDE shown in fig (iii) below, given that AX = BX = 6 cm, EY = CY = 4 cm, DE = DC = 5 cm, DX = 9 cm and DX is perpendicular to EC and AB.

If the length and the breadth of a room are increased by 1 metre, the area is increased by 21 square metres. If the length is increased by 1 metre and breadth is decreased by 1 metre the area is decreased by 5 square metres. Find the perimeter of the room.