KnowledgeBoat Logo
|

Mathematics

The following data represents the daily wages in rupees of a certain number of employees of a company :

Daily wages (in ₹)No. of Employees
30-408
40-5014
50-6012
60-7017
70-8020
80-9026
90-10013
100-11010

Use a graph to answer the following questions :

(a) Represent the above distribution by an ogive.

(b) Find the following on the graph drawn:

(i) median wage.

(ii) percentage of employees who earn more than ₹ 84 per day.

(iii) number of employees who earn ₹56 and below.

Statistics

25 Likes

Answer

Cumulative frequency distribution table :

Daily wages (in ₹)No. of employeesCumulative frequency
30-4088
40-501422
50-601234
60-701751
70-802071
80-902697
90-10013110
100-11010120

Here, n = 120, which is even.

Median = n2=1202\dfrac{n}{2} = \dfrac{120}{2} = 60th term.

The following data represents the daily wages in rupees of a certain number of 
employees of a company : Maths Competency Focused Practice Questions Class 10 Solutions.

Steps of construction :

1. Plot daily wages on x-axis.

2. Plot cumulative frequency on y-axis.

3. Mark points (40, 8), (50, 22), (60, 34), (70, 51), (80, 71), (90, 97), (100, 110) and (110, 120).

4. Draw a free hand curve passing through the points marked, strating from the lower limit of first class and terminating at upper limit of the last class.

5. Mark A = 60 on y-axis, draw a horizontal line which meets curve at B.

6. Through point B, draw a vertical line which meets x-axis at point C. The value of point C on x-axis is the median. ∴ Median wage is ₹74.

7. Mark D = 84 on x-axis, draw a vertical line which meets curve at E.

8. Through point E, draw a horizontal line which meets y-axis at point F. The value of point F on y-axis represents no. of employees earning less than or equal to ₹ 84 per day.

From graph,

F = 81.

No. of employees earning more than ₹ 84 per day = 120 - 81 = 39.

Percentage of employees earning more than ₹ 84 = No. of employees earning more than ₹ 84Total employees×100\dfrac{\text{No. of employees earning more than ₹ 84}}{\text{Total employees}} \times 100

=39120×100=3900120= \dfrac{39}{120} \times 100 = \dfrac{3900}{120} = 32.5 %.

9. Mark G = 56 on x-axis, draw a vertical line which meets curve at H.

10. Through point H, draw a horizontal line which meets y-axis at point I. The value of point I on y-axis represents no. of employees earning less than or equal to ₹ 56 per day.

From graph,

I = 30.

No. of employees earning less than or equal to ₹ 56 per day = 30.

Answered By

15 Likes


Related Questions