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Mathematics

The following table gives the distribution of the life time of 400 neon lamps :

Life time (in hours)Number of lamps
1500 - 200014
2000 - 250056
2500 - 300060
3000 - 350086
3500 - 400074
4000 - 450062
4500 - 500048

Find the median life time of a lamp.

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Answer

Cumulative frequency distribution table is as follows :

Life time (in hours)Number of lampsCumulative frequency
1500 - 20001414
2000 - 25005670 (14 + 56)
2500 - 300060130 (70 + 60)
3000 - 350086216 (130 + 86)
3500 - 400074290 (216 + 74)
4000 - 450062352 (290 + 62)
4500 - 500048400 (352 + 48)

Here, n = 400, n2=4002=200\dfrac{n}{2} = \dfrac{400}{2} = 200.

Cumulative frequency just greater than 200 is 216, belonging to class-interval 3000 - 3500

∴ Median class = 3000 - 3500

⇒ Class size (h) = 500

⇒ Lower limit of median class (l) = 3000

⇒ Frequency of median class (f) = 86

⇒ Cumulative frequency of class preceding median class (cf) = 130

By formula,

Median = l+(n2cff)×hl + \Big(\dfrac{\dfrac{n}{2} - cf}{f}\Big) \times h

Substituting values we get :

Median =3000+20013086×500=3000+3500086=3000+406.98=3406.98\Rightarrow \text{Median } = 3000 + \dfrac{200 - 130}{86} \times 500 \\[1em] = 3000 + \dfrac{35000}{86} \\[1em] = 3000 + 406.98 \\[1em] = 3406.98

Hence, median life = 3406.98 hours.

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