The height of a cone is 15 cm. If its volume is 1570 cm³, find the radius of the base. (Use π = 3.14)

Given,

Height of the cone (h) = 15 cm

Let radius of base of cone be r cm.

Volume of cone = 1570 cm³

Substituting values we get :

$\therefore \dfrac{1}{3}πr^2h = 1570 \\[1em] \Rightarrow r^2 = \dfrac{1570 \times 3}{πh} \\[1em] \Rightarrow r^2 = \dfrac{1570 \times 3}{3.14 \times 15} \\[1em] \Rightarrow r^2 = \dfrac{4710}{47.1} \\[1em] \Rightarrow r^2 = 100 \\[1em] \Rightarrow r = \sqrt{100} \\[1em] \Rightarrow r = 10 \text{ cm}.$

Hence, radius of the base = 10 cm.