The kinetic energy of an object of mass m, moving with a velocity of 5 ms^-1 is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?
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The kinetic energy of an object of mass m, moving with a velocity of 5 ms^-1 is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?

Work, Energy & Power

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KnowledgeBoat · Accepted Answer

Given, Kinetic Energy (K_E) = 25 J Velocity (v) = 5 ms^-1 We know, Kinetic Energy (K_E) = mv². Substituting we get, 25 = x m x 5² 25 x 2 = 25 x m m = m = 2 kg When velocity is doubled : v' = 10 ms^-1 m = 2 kg Substituting we get, K_E = x 2 x 10² K.E. = 100 J When velocity is increased three times, then v'' = 15 ms^-1 m = 2 kg Substituting we get, K_E = x 2 x 15² K.E. = 225 J Hence, Kinetic Energy becomes 100 J when velocity is doubled and it becomes 225 J when velocity is increased three times.

Science

The kinetic energy of an object of mass m, moving with a velocity of 5 ms^-1 is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?

Work, Energy & Power

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The kinetic energy of an object of mass m, moving with a velocity of 5 ms-1 is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?

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The kinetic energy of an object of mass m, moving with a velocity of 5 ms^-1 is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?