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Physics

The moment of a force of 20 N about a point O is 18 N-m. Find the distance of point of application of the force from the point O.

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Given,

moment of a force = 18 N-m

force = 20 N

distance = ?

Moment of force = force × distance

Substituting the values in the formula above, we get,

$18 = 20 \times \text{d} \\[0.5em] \Rightarrow d = \dfrac{18}{20} \\[0.5em] \Rightarrow d = 0.9 \text{ m} \\[0.5em]$

Hence, distance of point of application of the force from the point O = 0.9 m

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