The population of a village increases by 10% per year. If the present population of the village is 24,000; find it at the end of 2 years.

Given:

Percentage increase in village population per year = 10%

Present population of village = 24,000

Increase of population at the end of 1 year = 10% of previous population

= $\dfrac{10}{100} \times 24,000$

= $\dfrac{1}{10} \times 24,000$

= $\dfrac{24,000}{10}$

= $2,400$

Population at the end of 1 year = Population + Increase of population

= $24,000 + 2,400$

= $26,400$

Increase in population at the end of 2 year = 10% of previous population

= $\dfrac{10}{100} \times 26,400$

= $\dfrac{1}{10} \times 26,400$

= $\dfrac{26,400}{10}$

= $2,640$

Population at the end of 2 year = Previous population + Increase in population

= $26,400 + 2,640$

= $29,040$

Hence, the population after 2 year = 29,040