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Mathematics

The present population of a town is 200000. Its population increases by 10% in the first year and 15% in the second year. Find the population of the town at the end of two years.

Compound Interest

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Answer

By formula,

V = V0(1+r1100)(1+r2100)V0\Big(1 + \dfrac{r1}{100}\Big)\Big(1 + \dfrac{r_2}{100}\Big)

Putting values in formula we get,

V=200000(1+10100)(1+15100)=200000×110100×115100=20×110×115=253000.V = 200000\Big(1 + \dfrac{10}{100}\Big)\Big(1 + \dfrac{15}{100}\Big) \\[1em] = 200000 \times \dfrac{110}{100} \times \dfrac{115}{100} \\[1em] = 20 \times 110 \times 115 \\[1em] = 253000.

Hence, the population of the town at the end of two years is 253000.

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