The pressure on a surface is reduced by :

1. using high thrust
2. increasing the area of surface
3. decreasing the area of surface
4. none of these

increasing the area of surface

Reason — Larger the area on which a given thrust acts, lesser is the pressure exerted by it, as pressure is inversely proportional to the area of surface.

$\text{Pressure} = \dfrac{\text{Thrust}}{\text{Area}} \\[0.5em] \text{or} \\[0.5em] P = \dfrac{\text{F}}{\text{A}}$