The probability that a non-leap year has 53 Sundays is : 1. 1 2. 3. 4.

Question

KnowledgeBoat · Accepted Answer

There are 365 days in a non-leap year. No. of weeks = = 52 weeks and 1 day. Since, there is one sunday in a week, and one week has seven days. So, in order to have 53 sundays the 1 day that remains should also be sunday. P(that a non-leap year has 53 sundays) = . Hence, Option 2 is the correct option.

Mon.		6	13	20	27
Tue.		7	14	21	28
Wed.	1	8	15	22	29
Thu.	2	9	16	23	30
Fri.	3	10	17	24	31
Sat.	4	11	18	25
Sun.	5	12	19	26

Mathematics

The probability that a non-leap year has 53 Sundays is : 1. 1 2. 3. 4.

Probability

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Mathematics

The probability that a non-leap year has 53 Sundays is : 1. 1 2. 3. 4.

Probability

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Out of 800 identical articles some are selected and remaining are rejected. If the probability of an article to be rejected is 0.425; the number of rejected articles is :340800430560

Out of 800 identical articles some are selected and remaining are rejected. If the probability of an article to be rejected is 0.425; the number of rejected articles is :
340
800
430
560