Mathematics
The shaded region of the given diagram represents the lawn in the form of a house. On the three sides of the lawn there are flower-beds having a uniform width of 2 m.
(i) Find the length and the breadth of the lawn.
(ii) Hence, or otherwise, find the area of the flower-beds.
Mensuration
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Answer
Given:
Length of the lawn = 30 m
Breadth of the lawn = 12 m
Width of flowerbed = 2 m
New length of lawn = 30 - 2 - 2 m = 30 - 4 m = 26 m
New breadth of lawn = 12 - 2 m = 10 m
Hence, the length of lawn = 26 m and the breadth of lawn = 10 m.
(ii) Area of flowerbed = Area of AMPX + Area of XDCY + Area of NBYO
Area of AMPX = l x b = AM x MP
= 10 x 2 m2
= 20 m2
Area of XDCY = l x b = XD x DC
= 30 x 2 m2
= 60 m2
Area of NBYO = l x b = NB x BY
= 10 x 2 m2
= 20 m2
Area of flowerbed = 20 + 60 + 20 m2
= 100 m2
Hence, the area of flowerbed is 100 m2.
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