Mathematics
The sides of a triangle are x2 - 3xy + 8, 4x2 + 5xy - 3 and 6 - 3x2 + 4xy. Find its perimeter.
Answer
The sides of a triangle = (x2 - 3xy + 8), (4x2 + 5xy - 3) and (6 - 3x2 + 4xy)
Perimeter of triangle = sum of all its side.
(x2 - 3xy + 8) + (4x2 + 5xy - 3) + (6 - 3x2 + 4xy)
= x2 - 3xy + 8 + 4x2 + 5xy - 3 + 6 - 3x2 + 4xy
= (x2 + 4x2 - 3x2) + (- 3xy + 5xy + 4xy) + (- 3 + 6 + 8)
= 2x2 + 6xy + 11
Hence, perimeter of triangle = 2x2 + 6xy + 11
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