Solve the following pairs of linear equations:

$\dfrac{1}{2(x + 2y)} + \dfrac{5}{3(3x - 2y)} = -\dfrac{3}{2}$

$\dfrac{5}{4(x + 2y)} - \dfrac{3}{5(3x - 2y)} = \dfrac{61}{60}$

If x = 3, y = k is a solution of the equation 3x - 4y + 7 = 0, then the value of k is

1. 16

2. -16

3. 4

4. -4

If x = a, y = b is the solution of the equations x - y = 2 and x + y = 4, then the values of a and b are respectively,

1. 3 and 5

2. 5 and 3

3. 3 and 1

4. -1 and -3

The solution of the system of equations $\dfrac{4}{x} + 5y = 7 \text{ and } \dfrac{3}{x} + 4y = 5$ is

1. $x = \dfrac{1}{3}, y = -1$

2. $x = -\dfrac{1}{3}, y = 1$

3. x = 3, y = -1

4. x = -3, y = 1