The sum of two numbers is 4500. If 10% of one number is 12.5% of the other, find the numbers.

The sum of two numbers is 4500. Let the number be x. The other number is (4500 \- x). So, 10% of one number is 12.5% of the other number. 10% of x = 12.5% of (4500 \- x) By cross multiplying, we get : ⇒ 8x = 10(4500 \- x) ⇒ 8x = 45000 \- 10x ⇒ 8x \+ 10x = 45000 ⇒ 18x = 45000 ⇒ x = ⇒ x = 2500 Other number = (4500 \- x) = (4500 \- 2500) = 2000 Hence, the two numbers are 2500 and 2000.